android - Sum and difference beetwen hours in Java (over 24h) -

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i'm developing android app , need calculate times (with joda libs). know if exist java class this.

the cases calculate (in example):

case 1:

t1 = "13:40" t2 = "12:30" result = t1 + t2 --> 26:10

case 2:

t1 = "13:40" t2 = "12:30" result = t1 - t2 --> 1:10

case 2.1:

t1 = "13:40" t2 = "14:00" result = t1 - t2 --> -0:20

thanks!! :)

following jodatime-code handles both inputs , result temporal amounts, not points in time:

case 1:

periodformatterbuilder builder = new periodformatterbuilder(); builder.minimumprinteddigits(2); builder.printzeroalways(); builder.appendhours(); builder.appendliteral(":"); builder.appendminutes(); periodformatter pf = builder.toformatter();  period period1 = pf.parseperiod("13:40"); period period2 = pf.parseperiod("12:30"); period total = period1.plus(period2); period normalized = total.normalizedstandard(periodtype.time());  system.out.println("total period: " + total); // pt25h70m system.out.println("normalized period: " + normalized); // pt26h10m system.out.println("formatted normalized period: " + pf.print(normalized)); // 26:10

case 2 + 2.1:

periodformatterbuilder builder = new periodformatterbuilder(); builder.minimumprinteddigits(2); builder.printzeroalways(); builder.appendhours(); builder.appendliteral(":"); builder.appendminutes(); periodformatter pf = builder.toformatter();  period period1 = pf.parseperiod("13:40"); period period2 = pf.parseperiod("14:00");  boolean negative = false;  if (period1.tostandardduration().isshorterthan(period2.tostandardduration())) {   period tmp = period1;   period1 = period2;   period2 = tmp;   negative = true; }  period total = period1.minus(period2); period normalized = total.normalizedstandard(periodtype.time()); system.out.println("normalized period: " + (negative ? "-" : "") + normalized); system.out.println(   "formatted normalized period: " + (negative ? "-" : "") + pf.print(normalized) ); // -00:20

note due insufficient sign handling of jodatime (which likes print sign not in front midth inside period expression) clunky workaround necessary.


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