JavaScript if(x) vs if(x==true) -

in javascript , in cases following statements won't logically equal ?

if(x){} 

and

if(x==true){} 

thanks

they not @ equal.

if (x) 

checks if x truthy later checks if boolean value of x true.

for example,

var x = {}; if (x) {     console.log("truthy"); } if (x == true) {     console.log("equal true"); } 

not object, string (except empty string), number (except 0 (because 0 falsy) , 1) considered truthy, not equal true.

as per ecma 5.1 standards, in if (x), truthiness of x decided, per following table

+-----------------------------------------------------------------------+ | argument type | result                                                | |:--------------|------------------------------------------------------:| | undefined     | false                                                 | |---------------|-------------------------------------------------------| | null          | false                                                 | |---------------|-------------------------------------------------------| | boolean       | result equals input argument (no conversion). | |---------------|-------------------------------------------------------| | number        | result false if argument +0, −0, or nan;| |               | otherwise result true.                         | |---------------|-------------------------------------------------------| | string        | result false if argument empty      | |               | string (its length zero); otherwise result  | |               | true.                                                 | |---------------|-------------------------------------------------------| | object        | true                                                  | +-----------------------------------------------------------------------+ 

note: last line object, includes both objects , arrays.

but in later case, per the abstract equality comparison algorithm,

if type(x) boolean, return result of comparison tonumber(x) == y. if type(y) boolean, return result of comparison x == tonumber(y). 

value of x converted number , number checked against true.

note:

in javascript, true 1 , false 0.

console.log(1 == true); # true console.log(0 == false); # true