c++ - How to pass array of function pointers to another function -

i have got 2 functions:

char* odwroc(char* nap, int n)  char* male(char* nap, int n)  

i have defined pointer kind functions

 typedef char*(*pointertofunction )( char*, int ); 

then in used definition in main:

 pointertofunction ptr1 = odwroc;  pointertofunction ptr2 = male; 

but have create function first parameter gets array of pointers function , stuck. don't know how define array of pointers function , how modyfikuj parameter list should like.

void modyfikuj(char* pointertofunction *pointerarray, int length, char* nap2, int n){  } 

try this:

pointertofunction mojefunkcje[] = { odwroc, male};  modyfikuj( mojefunkcje, ...);      // pass array fo modyfikuj()  void modyfikuj( pointertofunction* funtab, ...) {     funtab[0]( string, liczba);    // call  odwroc( string, liczba)     funtab[1]( string, liczba);    // call  male( string, liczba) }