arrays - Matching exact fields -

i have question.

i working large list data , need omit in field quantity of '0'. problem is, , see why, omitting other things contain '0', i.e. 100, 101, pretty contains 0 exact value of 0.

example table:

id   name  food   quantity   price 1   josh   hotdog   1   5.00 2   josh   hotdog   100   5.0 3   josh   hotdog   101   5.00 4   josh   hotdog   0   5.00 5   josh   hotdog   1   5.00 

the row omit has 'id' number '4'. not need rows quantity of 0. code have used command prompt one-liner apply batch files. looks this.

perl i.bak -af\t -ne "print if $f[3] =~ "/[0]/" file.txt. 

now know not work because character class randomizes '0'. in other words saying "if" there '0' anywhere in field print it(or "unless", have "if" on 1 liner time see results).

just looking exact match of '0' , wondering if possible method using.

change

perl i.bak -af\t -ne "print if $f[3] =~ "/[0]/" file.txt. 

to

perl i.bak -af\t -ne 'print if $f[3] ne "0"' file.txt 

or

perl i.bak -af\t -ne 'print if $f[3] != 0' file.txt 

or

perl i.bak -af\t -ne 'print if $f[3] !~ m/^0$/' file.txt 

and try again.

your $f[3] =~ /[0]/ true if $f[3] includes character 0.