python - How to get all mappings between two lists? -

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we have 2 lists, , b:

a = ['a','b','c'] b = [1, 2]

is there pythonic way build set of maps between , b containing 2^n (here 2^3=8)? is:

[(a,1), (b,1), (c,1)] [(a,1), (b,1), (c,2)] [(a,1), (b,2), (c,1)] [(a,1), (b,2), (c,2)] [(a,2), (b,1), (c,1)] [(a,2), (b,1), (c,2)] [(a,2), (b,2), (c,1)] [(a,2), (b,2), (c,2)]

using itertools.product, it's possible tuples:

import itertools p = it.product(a, b) [p p in p]

which gives:

out[3]: [('a', 1), ('a', 2), ('b', 1), ('b', 2), ('c', 1), ('c', 2)]

you can itertools.product , zip

from itertools import product print [zip(a, item) item in product(b, repeat=len(a))]

output

[[('a', 1), ('b', 1), ('c', 1)],  [('a', 1), ('b', 1), ('c', 2)],  [('a', 1), ('b', 2), ('c', 1)],  [('a', 1), ('b', 2), ('c', 2)],  [('a', 2), ('b', 1), ('c', 1)],  [('a', 2), ('b', 1), ('c', 2)],  [('a', 2), ('b', 2), ('c', 1)],  [('a', 2), ('b', 2), ('c', 2)]]

product(b, repeat=len(a)) produces 

[(1, 1, 1),  (1, 1, 2),  (1, 2, 1),  (1, 2, 2),  (2, 1, 1),  (2, 1, 2),  (2, 2, 1),  (2, 2, 2)]

then pick each element product , zip a, desired output.


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