python - Vending Machine Program (Calculate the amount that has to inserted,etc.) -
i want write program simulate vending machine , calculate change (which has returned you) based on amount paid. given cost, user should first prompted add more money until cost met/exceeded payment.
assume change given in coins , coins come in following denominations: 1c, 5c, 10c, 25c, $1
here program:
x = eval(input("enter cost (in cents):\n")) b = 0 in range(x+500): if x<5 , x>=b: b += 1 print("deposit coin or note (in cents):") print(1) diff = b-x in range(diff): onecents = diff//1 new_onecents = diff - (onecents*1) print("your change is:") if onecents != 0: print(onecents,"x 1c") break elif x<10 , x>=b: b += 5 print("deposit coin or note (in cents):") print(5) diff = b-x in range(diff): fivecents = diff//5 new_fivecents = diff - (fivecents*5) onecents = new_fivecents//1 new_onecents = new_fivecents - (onecents*1) print("your change is:") if fivecents != 0: print(fivecents,"x 5c") if onecents != 0: print(onecents,"x 1c") break elif x<25 , x>=b: b += 10 print("deposit coin or note (in cents):") print(10) diff = b-x in range(diff): tencents = diff//10 new_tencents = diff - (tencents*10) fivecents = new_tencents//5 new_fivecents = new_tencents - (fivecents*5) onecents = new_fivecents//1 new_onecents = new_fivecents - (onecents*1) print("your change is:") if tencents !=0: print(tencents,"x 10c") if fivecents != 0: print(fivecents,"x 5c") if onecents != 0: print(onecents,"x 1c") break elif x<100 , x>=b: b += 25 print("deposit coin or note (in cents):") print(25) diff= b-x in range(diff): quarters = diff//25 new_quarters = diff - (quarters*25) tencents = new_quarters//10 new_tencents = new_quarters - (tencents*10) fivecents = new_tencents//5 new_fivecents = new_tencents - (fivecents*5) onecents = new_fivecents//1 new_onecents = new_fivecents - (onecents*1) print("your change is:") if quarters !=0: print(quarters,"x 25c") if tencents !=0: print(tencents,"x 10c") if fivecents != 0: print(fivecents,"x 5c") if onecents != 0: print(onecents,"x 1c") break elif x<500 , x>b: print("deposit coin or note (in cents):") print(100) b += 100 diff = b-x in range(diff): quarters = diff//25 new_quarters = diff - (quarters*25) tencents = new_quarters//10 new_tencents = new_quarters - (tencents*10) fivecents = new_tencents//5 new_fivecents = new_tencents - (fivecents*5) onecents = new_fivecents//1 new_onecents = new_fivecents - (onecents*1) print("your change is:") if quarters !=0: print(quarters,"x 25c") if tencents !=0: print(tencents,"x 10c") if fivecents != 0: print(fivecents,"x 5c") if onecents != 0: print(onecents,"x 1c") break elif x<(x+500) , x>=b: print("deposit coin or note (in cents):") print(500) b += 500 diff = b-x in range(diff): onedollars = diff//100 new_onedollars = diff - (onedollars * 100) quarters = new_onedollars//25 new_quarters = new_onedollars - (quarters*25) tencents = new_quarters//10 new_tencents = new_quarters - (tencents*10) fivecents = new_tencents//5 new_fivecents = new_tencents - (fivecents*5) onecents = new_fivecents//1 new_onecents = new_fivecents - (onecents*1) print("your change is:") if onedollars != 0: print(onedollars,"x $1") if quarters !=0: print(quarters,"x 25c") if tencents !=0: print(tencents,"x 10c") if fivecents != 0: print(fivecents,"x 5c") if onecents != 0: print(onecents,"x 1c") break when run program , follow instructions should this:
enter cost (in cents): 1000 deposit coin or note (in cents): 500 deposit coin or note (in cents): 500 deposit coin or note (in cents): instead get:
enter cost (in cents): 1000 deposit coin or note (in cents): 500 deposit coin or note (in cents): 500 deposit coin or note (in cents): 500 change is: 5 x $1 also expected output:
enter cost (in cents): 3 deposit coin or note (in cents): 1 deposit coin or note (in cents): 1 deposit coin or note (in cents): 1 however get:
enter cost (in cents): 3 deposit coin or note (in cents): 1 deposit coin or note (in cents): 1 deposit coin or note (in cents): 1 deposit coin or note (in cents): 1 change is: 1 x 1c the rest work out , correct.
thanks guys (especially @jonrsharpe). here solution (in code form):
def vend(): """simulate vending machine, taking user input , returning remainder.""" total = eval(input("enter cost (in cents):\n")) inserted = 0 while inserted < total: inserted += eval(input("deposit coin or note (in cents):\n")) if inserted > total: sum = inserted - total if sum != 0: print("your change is:") dollars = sum//100 if dollars != 0: print(dollars,'x $1') quarters = (sum - dollars*100)//25 if quarters != 0: print(quarters,'x 25c') ten_cents = (sum - dollars*100 - quarters*25)//10 if ten_cents != 0: print(ten_cents,'x 10c') five_cents = (sum - dollars*100 - quarters*25 - ten_cents*10)//5 if five_cents != 0: print(five_cents,'x 5c') one_cents = (sum - dollars*100 - quarters*25 - ten_cents*10 - five_cents*5)//1 if one_cents != 0: print(one_cents,'x 1c') vend()
your specific error stems fact not deal correctly case reach total - overshoot, have give change. however, code long , complex , difficult figure out doing @ each stage.
a few general coding suggestions:
evalbad idea; better useint(input(...)), make fuss if user doesn't enter integer.- your outer
forloop shouldwhileloop, rather guessing maximum number of iterations (which run, after you've made change!) - you have a lot of repeated code , hard-coded values; whenever write similar things repeatedly consider splitting them out function arguments, or kind of loop.
also, reading description, specifically:
given cost, user should first prompted add more money until cost met/exceeded payment.
i think supposed allowing user input coins rather guessing enter.
here 1 possible implementation:
def vend(): """simulate vending machine, taking user input , returning remainder.""" total = int(input("enter cost (in cents): ")) inserted = 0 while inserted < total: inserted += int(input("deposit coin or note (in cents): ")) if inserted > total: return make_change(inserted - total) def make_change(remainder): """calculate coins required make change equal amount.""" coins = ["$1", "25c", "10c", "5c", "1c"] amounts = [int(coin[:-1]) if coin.endswith("c") else 100 * int(coin[1:]) coin in coins] counts = [0 _ in coins] index, amount in enumerate(amounts): counts[index] = remainder // amount remainder %= amount return ", ".join("{0} x {1}".format(count, coin) count, coin in zip(counts, coins) if count) note division of responsibility between 2 functions, make easier test each 1 separately, , appropriate use of for , while loops minimise repetition. also, have made amounts , paid in make_change depend on coins, have change in 1 place add new coins.
example usage:
>>> vend() enter cost (in cents): 135 deposit coin or note (in cents): 100 deposit coin or note (in cents): 50 '1 x 10c, 1 x 5c'
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